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4x^2+90x-900=0
a = 4; b = 90; c = -900;
Δ = b2-4ac
Δ = 902-4·4·(-900)
Δ = 22500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{22500}=150$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(90)-150}{2*4}=\frac{-240}{8} =-30 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(90)+150}{2*4}=\frac{60}{8} =7+1/2 $
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